Given: a photograph is 5 inches wide and 7 inches tall.
He wants to enlarge the photo to fit in a frame that is 32 inches tall.
So, the length and the width will be scaled proportionally
So, the scale factor = r= new length over the lod length
[tex]r=\frac{32}{7}[/tex]It must be the same ratio: new width to old width
Let the new wide = x
so,
[tex]\frac{x}{5}=\frac{32}{7}[/tex]solve for x:
[tex]x=\frac{32}{7}\cdot5=\frac{160}{7}=22\frac{6}{7}in[/tex]So, the answer will be: the new width = 22 6/7 inches