1) Considering the group of the longest worms size is 1 and 1/2 inch and the shortest ones have the size of 3/4 of an inch.
2) Firstly, let's convert the mixed number to an improper fraction and then subtract.
[tex]1\frac{1}{2}=\frac{(2\cdot1+1)}{2}=\frac{3}{2}[/tex]We do this by conserving the denominator and multiplying it by the whole number and adding to the numerator:
To find the Least Common Multiple (LCM), we proceed this way:
We divide those numbers for a prime number, that divide both (2 and 4) and go on until we reach 1. Then we multiply the numbers on the right. ( 2 and 2)
3) Now let's subtract then. Since they have different denominators, then we must calculate the Least Common Multiple of both:
[tex]\begin{gathered} \frac{3}{2}-\frac{3}{4} \\ \frac{(4\colon2\times3)-(4\colon4\times3)}{4}= \\ \frac{6-3}{4}= \\ \frac{3}{4} \end{gathered}[/tex]The LCM between 2,4 is 8. So the difference between the longest size (3/2 inches or 1 1/2 ) and the shortest 3/4 is equal to 3/4
