Use the unit circle to get the values in the given expression:
Coordinates are (cosine, sine)
[tex]\begin{gathered} sin(\frac{\pi}{3})-cos(\frac{\pi}{6}) \\ \\ sin(\frac{\pi}{3})=\frac{\sqrt{3}}{2} \\ \\ cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2} \\ \\ s\imaginaryI n(\frac{\pi}{3})-cos(\frac{\pi}{6})=\frac{\sqrt{3}}{2}-\frac{\sqrt{3}}{2}=0 \end{gathered}[/tex]
Then, the exact value of the given expression is 0
