From the given picture, the hypotenuse is 100, then, we get
[tex]\begin{gathered} \sin B=\frac{28}{100} \\ \text{tanB}=\frac{28}{96} \end{gathered}[/tex]
Which in simplest form is given by
[tex]\begin{gathered} \sin B=\frac{7}{25} \\ \tan B=\frac{7}{24} \end{gathered}[/tex]
