Answer :

we will first change the hours for minutes

Danna

[tex]\frac{3}{10}\text{hours}\longrightarrow18\text{minutes}[/tex]

Steven

[tex]\frac{1}{6}\text{hours}\longrightarrow10\text{minutes}[/tex]

so, the new information is

Danna read 1/4 of the book in 18 minutes

Steven read 1/5 of the book in 10 minutes

now we express the time in a single minute and on pages of book

For Danna we divide all the ralation between 18

so

[tex]\begin{gathered} \frac{\frac{1}{4}}{18}book\longrightarrow\frac{18}{18}\text{minutes} \\ \\ \frac{1}{72}book\longrightarrow1\text{minute} \\ \\ \frac{1}{72}\times60\text{pages}\longrightarrow1\text{minute} \\ \\ 0.83\text{ pages}\longrightarrow1minute \end{gathered}[/tex]

For steven we divide all the relation between 10

so

[tex]\begin{gathered} \frac{\frac{1}{5}}{10}\text{book}\longrightarrow\frac{10}{10}\text{minutes} \\ \\ \frac{1}{50}\text{book}\longrightarrow1\text{minute} \\ \\ \frac{1}{50}\times60\text{pages}\longrightarrow1\text{minute} \\ \\ 1.2pages\longrightarrow1minute \end{gathered}[/tex]

we can conclude that steven reads more pages per minute than Dana because he she reads 0.83 pages per minute and steven 1.2 pages per minute

so the right statement is option B