The percentage yield of Fe is 69.18%
Hello
To solve this question, we have to find the theoritical yield of the reaction from the equation of reaction and using the information to calculate the percentage yield with the given actual yield.
The theoritical yield is given already in the question as 4.51g
This is the ratio between the actual yield to the theoritical yield multiplied by 100
Mathematically;
[tex]\begin{gathered} \text{percentage yield }=\frac{actual\text{ yield}}{theoritical\text{ yield }}\times100 \\ \end{gathered}[/tex]Data;
Actual Yield = 3.12g
Theoritical Yield = 4.51g
Percentage Yield = ?
Substitute the values into the equaton above and solve.
[tex]\begin{gathered} \text{percentage yield}=\frac{3.12}{4.51}\times100 \\ \text{percentage yield }=69.18\text{ \%} \end{gathered}[/tex]The percentage yield of Fe in the reaction is 69.18%