1) List known and unknown values
Compound A: CO2
Molar Mass: 44.01 g/mol
Rate of effusion: 1.0
Compound B: CxH2n+2
Rate of effusion: 1.206
Molar mass:
2) Graham's law
[tex]\frac{Rate_A}{Rate_B}=\sqrt[]{\frac{MM_B}{MM_A}}[/tex]Plug in values and solve for MMB
[tex]\frac{1.0}{1.206}=\sqrt[]{\frac{MM_B}{44.01\frac{g}{mol_{}}}}[/tex][tex](\frac{1.0}{1.206})^2\cdot44.01=MM_B[/tex][tex]MM_B=30.26\frac{g}{\text{mol}}[/tex]The molar mass of CxH2n+2 is 30.26 g/mol
3) The molecular mass of the unknown compound
The molar mass of CH4 is 16.04 g/mol
[tex]\text{Ratio}=\frac{30.26}{16.04}=1.89[/tex]The ratio is 2. So, x is equal to 2
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