The work done on a sample of gas at the external pressure of 2660 mm Hg is 0.088kJ.
Work is carried out whenever a pressure moves something over a distance. we may calculate the power transferred, or work finished, with the aid of multiplying the pressure through the space moved inside the direction of the force.a pressure need to be exerted and there ought to be movement or displacement within the route of the force. The paintings completed by a pressure appearing on an object is same to the significance of the pressure multiplied with the aid of the gap moved in the course of the pressure.
W = PΔV
P = 2660 mmHg
= 2660/760
= 3.5 atm
1 atm = 101.3 J
= 3.5 × 101.3 J
= 354.55 J
W = - 354.55 × 10⁻³ KJ
W = - 354.55 × 10⁻³(0.63 - 0.88)
= - 354.55 × (-0.25)
= 0.088KJ answer
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