The volume will be one third of the original volume of an ideal gas.
Boyle’s law depicts the relationship between the pressure ,volume and the temperature of a gas. Boyle’s law states that the pressure of a gas is inversely proportional to its volume at a constant temperature.
P ∝ 1 / V
Or, PV = k
When the temperature is kept constant.
According to the question, when the pressure is increased from 2 atm to 6 atm , the pressure is increases thrice ,hence the volume will decrease three times simultaneously of the original volume of 1 mol of an ideal gas.
The equation of the Boyle’s law is; P1V1 = P2V2
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