A sample of methane is placed in a 10.0-L container at 25°C and 725 mmHg. The gas sample is then moved to a 7.50-L container at 25°C. What is the gas pressure in the second container?



Answer :

The pressure in second container is 966.6 mmHg.

An ideal gas's connection between pressure and volume can be explained using Boyle's Law. Volume and pressure are inversely connected, so a decrease in volume will result in an increase in pressure. It can be written as the equation follows:

P1V1=P2V2

The initial prerequisite in this scenario is a 10.0L volume and an 725 mmHg pressure. Then the system switched to the second situation, which has a 7.50L capacity and an unknown pressure. There will be pressure to:

P1V1= P2V2

P2 = P1 X V1/V2

P2 = 725 X 10/7.50

P2 = 966.6 mmHg

Learn more about Boyle’s Law:

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