Answer :
A correct option is an option (c) with a rectangle with sides measuring 5 and 2 and a rectangle with sides measuring 2 and 5.
Given :
If a rectangle has a perimeter of 14.
i.e. Perimeter = 14cm
Area of rectangle = 10[tex]cm^{2}[/tex]
The formula for the perimeter of a rectangle = 2(Length + Breadth)
Assume, Length = L and breadth = B
14 = 2(L+B)
L+B = 7cm
L = 7-B .... (1)
The formula for the area of the rectangle = Length x Breadth
10 = L x B ..... (2)
Putting the value of L from equation (1) into (2). We get,
10 = (7-B) x B
10 = 7B - [tex]B^{2}[/tex]
[tex]B^{2}[/tex] -7B + 10 = 0
B(B-5) -2(B-5) = 0
(B-5) (B-2) = 0
So, B = 5, B =2
Putting this value of B in (1) we get,
L = 5 at B =2 and L=2 at B=5.
So, the one side (L=5) at another side (B=2) and the one side (L=2)at another side (B=5) is the correct option.
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