Answer :

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Answer:  [tex]y= \frac{1}{10}x[/tex]

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Given: [tex]\textsf{Slope = 1/10 and goes through (20, 2)}[/tex]

Find: [tex]\textsf{Slope in slope-intercept form}[/tex]

Solution: First we need to plug into the point slope formula which is [tex](y - y_1) = m(x - x_1)[/tex].  Let us plug in the values first and then solve for the slope-intercept form.

Plug in the values

  • [tex](y - y_1) = m(x - x_1)[/tex]
  • [tex](y - 2) = \frac{1}{10}(x - 20)[/tex]

Simplify

  • [tex]y - 2 = (\frac{1}{10} * x)+(\frac{1}{10}*-20)[/tex]
  • [tex]y - 2 = \frac{1}{10}x-2[/tex]
  • [tex]y - 2 + 2 = \frac{1}{10}x-2 + 2[/tex]
  • [tex]y= \frac{1}{10}x[/tex]

Answer: Therefore, the final answer in slope-intercept form for the line with a slope of 1/10 that passes through the point (20, 2) is [tex]y= \frac{1}{10}x[/tex]