two in phase loudspeakers are some distance apart. a person stands 5.80 m from one speaker and 4.00 m from the other. what is the second lowest frequency at which the person will hear constructive interference? the speed of sound in air is 348 m/s.



Answer :

Due to the distance between two in phase loudspeakers, 348Hz is the second lowest frequency at which a listener will detect constructive interference. A person is 5.80 metres away from one speaker.

The frequency of an event is its repetitions per unit of time. When contrasting it with spatial frequency, it is also sometimes referred to as temporal frequency.

5.80 metres separate each speaker from the listener.

The separation between each person is 4.00 metres.

The shortest wavelength corresponds to the longest frequency.

The difference between the speakers needs to be calculated.

d=5.80-4.00 =1.8 m is the distance between the speakers.

That much is obvious.

The lengthiest wavelength has the following formula: lamda = d

lamda = 1.8/2 = 0.9

f = 348/0.9 = 348Hz

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