Answer:
2 meters
Explanation:
What we know from the problem are:
From the acceleration formula:
[tex] \displaystyle{ a = \dfrac{v - u}{t}}[/tex]
Substitute in:
[tex] \displaystyle{ - 0.25 \ \text{m/s}^{2} = \dfrac{ - 1 \ \text{m/s}}{t}} \\ \\ \displaystyle{ - 0.25 \ \text{m/s}^{2} \ \cdot t = - 1 \ \text{m/s}} \\ \\ \displaystyle{ t = \dfrac{ - 1 \ \text{m/s}}{ - 0.25 \ \text{m/s}^{2} }} \\ \\ \displaystyle{ t = 4 \ \text{s}}[/tex]
Now we know that at 4 seconds, the ladybug is at rest. Therefore, from the distance formula:
[tex] \displaystyle{s = ut + \dfrac{1}{2}a {t}^{2} }[/tex]
Substitute in:
[tex] \displaystyle{s = (1)(4) + \dfrac{1}{2}( - 0.25) {(4)}^{2} } \\ \\ \displaystyle{s = 4+ \dfrac{1}{2}( - 0.25) (16) } \\ \\ \displaystyle{s = 4 - 0.25 \cdot 8} \\ \\ \displaystyle{s = 4 - 2} \\ \\ \displaystyle{s = 2 \ \text{meters}}[/tex]
Therefore, she will cover distance of 2 meters.