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What is the total volume of gases produced at 1092 K and 1.00 atm pressure when 320 g of ammonium nitrite undergoes the following decomposition reaction? NHANOz(s) --> Nz(g) + 2H,O(g) 4x22.4L 22.4L 20x22.4L 5x224L 60x22.4L



Answer :

The total volume of gas produced at 1092 K and 1 atm is 34136.61 L.

The balanced chemical reaction for the above reaction is given as,

NaNO₃ → NaNO₂ + O₂

By ideal gas equation,

PV = nRT

where,

P is pressure, V is volume, n is no. of moles, R is gas constant and T is the temperature in Kelvin.

n = given mass / molecular mass

n = 320 / 85 = 3.76

Substituting the values in the equation we get,

1 × V = 3.76 × 8.314 × 1092

⇒ V = 34136.61 L

Hence, the volume is 34136.61 L.

Learn more about total volume from the link given below.

https://brainly.com/question/13408455

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