12) The reaction of 50 mL of C12 gas with 50 mL of CH4 gas via the equation: C12 (g) + CH4 (g) → HCl (g) + CH3C1 (g)
will produce a total of
A) 100
mL of products if pressure and temperature are kept constant.
B) 50
C) 200
D) 150
E) 250