Apply what you know about rates from mathematics to a problem involving water consumption. An aquifer holds 146,000 cubic feet of water. Water exits through a well at a steady rate of 500 cubic feet per day, and the aquifer is replenished at a constant rate of x cubic feet per day. If the water in the aquifer is used up in a year (365 days), what is the value of x? ignore evaporation and other losses.



Answer :

The value of x found by expressing the information as an equation is 100

What is an equation?

An equation is a statement usually made using mathematical symbols, numbers and variables, that consists of joining two expressions with an 'equals' sign.

The volume of water in the aquifer = 146,000 ft³

The rate at which water exits the aquifer daily = 500 ft³ per day

Rate at which the aquifer is replenished = x ft³ per day

The time it takes the water to be used up = 1 year

The number of days in a year = 365 days

The value of x can be found by expressing the information as an equation as follows;

The sum of the volume of water in the aquifer and the volume of water that replenishes the aquifer in a year, less the water that exits the aquifer in a year is zero, therefore;

Water in the aquifer; 146,000 - 500 × 365 + x × 365 = 0

-36500 + 365·x = 0

365·x = 36500

x = 36500 ÷ 365 = 100

x = 100

The value of x is 100

The water is replenished at 100 cubic feet per day

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