An SRS of 25 students at UH gave an average height of 5.6 feet and a standard deviation of .3 feet. Construct a 90% confidence interval for the mean height of students at UH.



Answer :

Margin of error for the given standard deviation is  m = 5.497 , 5.703

What is standard deviation?

Standard Deviation is a measure that shows what quantity variation (such as unfold, dispersion, spread,) from the mean exists. the quality deviation indicates a “typical” deviation from the mean. it's a well-liked live of variability as a result of it returns to the first units of live of the info set.

Main body:

formula for confidence interval is :

m = x-bar ± z* σ/√n

given information =

n = 25

σ = 0.3

mean = 5.6 ft

C.I. = 90% = 0.9

value of 0.9 in z - table = 0.816

substituting value ,

m = 5.6 ±(0.816) * 0.3/√25

m = 5.6 ± 0.103

m = 5.497 , 5.703

Hence margin of error is m = 5.497 , 5.703

to know more about standard deviation click on the link below

https://brainly.com/question/475676

#SPJ4

Other Questions