An electron is accelerated through 2,400 V from rest and then enters a region where there is a uniform 1.70-T magnetic field. What are (a.) the maximum and (b.) minimum magnitudes of the magnetic force acting on this electron?



Answer :

The magnetic force operating on this electron has a maximum value of 79.02 x 10^-13 N; its minimum magnitude is zero when the electron goes in the magnetic field's direction.

The total of all forces exerted on an object is referred to as the magnitude of the force. A crucial physics measurement is calculating the magnitudes of forces. Regardless of the direction in which it works, a force's "magnitude" is its "size" or "strength."

The magnetic field, which is the region around a magnet that exerts a magnetic force and is caused by moving electric charges, surrounds an electric charge similarly to how an electric field does the same for an electric charge. A visual representation of magnetic fields is made using magnetic field lines.

Let v represent the velocity an electron gains in an electric field.

Charge is applied with a potential difference of V q = 1/2 m v2 V. q, m denotes charge mass, and v denotes acquired velocity.

2400 x 1.6 x 10^-19 =0.5 x 9.1 x 10^31 x v2, where v2 = 844 x 10^12 v and v = 29.05 x 10^6 m/s.

When an electron moves perpendicular to the magnetic field, the strongest force is applied to it.

Maximum force = Bqv, where B is the magnetic field, q is the charge on the electron, and v is the electron's velocity, resulting in a force of 1.7 x 1.6 x 10^-19 x 29.05 x 10^6 = 79.02 x 10^-13 N.

When an electron moves in the magnetic field's direction, the minimum force is zero.

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