a simple harmonic oscillator has amplitude 0.42 m and period 3.8 sec. what is the maximum acceleration?

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20-12-2022
Physics

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a simple harmonic oscillator has amplitude 0.42 m and period 3.8 sec. what is the maximum acceleration?

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smecloudbird17 smecloudbird17 · Answer 1 · 2022-12-23T08:36:56-05:00

A basic harmonic oscillator has a 0.42 m amplitude and a 3.8 sec period. The maximum acceleration in the simple harmonic motion will be 1.144 rad/s².

Given that,

Amplitude of simple harmonic motion = 0.42 m

Time period of oscillation T = 3.8 sec

We have to find the maximum acceleration, but before that we have to find the angular frequency

The relation for angular frequency is

ω = (2*π)/T = (2* 3.14)/3.8 = 1.65 rad/sec

Maximum acceleration is given by, α = ω²* A = 1.65²* 0.42 = 1.144 rad/s²

Thus, maximum acceleration in the simple harmonic motion will be 1.144 rad/s².

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