Calculate the effective value of g, the acceleration of gravity, at (a) 6400 m, and (b) 6400 km, above the earth's surface.

Question

14-11-2022
Physics

Answered

Calculate the effective value of g, the acceleration of gravity, at (a) 6400 m, and (b) 6400 km, above the earth's surface.

Answer :

Other Questions

a pendulum clock on the surface of the earth has a period of 1.00s . on a distant planet, the length of teh pendulum mst be shortened to have a period of 1.00s.

a 1.4 kg block slides across a rough surface such that it slows down with an acceleration of 1.25 m/s2 . what is the coefficient of friction between the block a

3. If a truck has a linear acceleration of 1.85 m/s² and the wheels have an angular acceleration of 5.23 rad/s2, what is the diameter of the wheels?

which trip would require the greatest energy expenditure? a trip from the moon's surface to a colony at the l5 lagrange point a trip from a colony at the l5 lag

a group of tourists walk a km down the main street of a town at a speed of v km/hr. then, they walked twice that distance down a side road. how much time t (in

. a projectile is launched at an angle of and lands 20 s later at the same height as it was launched. (a) what is the initial speed of the projectile? (b) what

Write down the value of the following quantities into powers of tens. (without prefixes on the units)1. 60 ps = 2. 500 mg =3. 20000 mm = 4. 400 ns = 5.250 ug =6

Figure 23-43 shows cross-sections through two large, parallel, nonconductingsheets with identical distributions of positive charge with surface chargedensity σ

mary applies a force of 71 n to push a box with an acceleration of 0.47 m/s2. when she increases the pushing force to 83 n, the box's acceleration changes to 0.

a cube of wood having an edge dimension of 20.0 cm and a density of 650. kg/m3 floats on water. (a) what is the distance from the horizontal top surface of the

aditmarkas98 aditmarkas98 · Answer 1 · 2022-11-18T16:50:45-05:00

The gravitational acceleration at 6400 m is 9.74 m/s² and at 6400 km is 2.43 m/s².

We need to know about the gravitational field to solve this problem. The gravitational field is the area where affected by gravitational force. The magnitude of the gravitational field can be calculated by this equation

g = G . m / (R+r)²

where g is the gravitational field, G is gravitational constant (6.67 x 10¯¹¹ Nm²/kg²), m is the mass of the planet and r is the radius of the planet

From the question above, we know that

m = 5.94 x 10²⁴ kg

R = 6371000 m

ra = 6400 m

rb = 6400000 m

Find the gravitational acceleration at 6400 m

g = G . m / (R + r)²

g = 6.67 x 10¯¹¹ . 5.94 x 10²⁴ / (6371000 + 6400)²

g = 9.74 m/s²

Find the gravitational acceleration at 6400 km

g = G . m / (R + r)²

g = 6.67 x 10¯¹¹ . 5.94 x 10²⁴ / (6371000 + 6400000)²

g = 2.43 m/s²

Find more on gravitational acceleration at: https://brainly.com/question/14080810

#SPJ4