Solution:
Given:
[tex](2x+5)(3x-2)[/tex]To get the one that is equivalent, we expand the first bracket with the terms in the second bracket.
[tex]\begin{gathered} (2x+5)(3x-2) \\ (2x+5)(3x)+(2x+5)(-2) \end{gathered}[/tex]
Therefore, (2x + 5)(3x - 2) = (2x + 5)(3x) + (2x + 5)(-2)