Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 56.3 degrees.Low Temperature (OF) 40-44 45-49 50-54 55-59 60-64 0Frequency37 11 5 2degrees.The mean of the frequency distribution is(Round to the nearest tenth as needed.)



Answer :

To find the mean of a frequency distribution with intervals, we first need to find the midpoint of each interval.

We do that by adding the limits of each interval and dividing by 2:

1

[tex]\frac{40+44}{2}=42[/tex]

2

[tex]\frac{45+49}{2}=47[/tex]

3

[tex]\frac{50+54}{2}=52[/tex]

4

[tex]\frac{55+59}{2}=57[/tex]

5

[tex]\frac{60+64}{2}=62[/tex]

Now, we multiply these midpoints by the frequency of each interval and sum them:

[tex]\begin{gathered} 3\cdot42+7\cdot47+11\cdot52+5\cdot57+2\cdot62 \\ 126+329+572+285+124=1436 \end{gathered}[/tex]

Now, we divide this sum by the sum of the frequencies, and this will be the mean.

[tex]m=\frac{1436}{3+7+11+5+2}=\frac{1436}{28}=51.3[/tex]

So, the mean calculated by using the frequency distribution is 51.3, which is lower than the actual mean of the data, 56.3.