ANSWER and EXPLANATION
We have the right angled triangle with one given side and one given angle.
To find x and y, we have to use trigonometric functions SOHCAHTOA.
We have that
[tex]\sin 30\text{ = }\frac{opposite}{hypotenuse}\text{ and cos30 = }\frac{adjacent\text{ }}{hypotenuse}[/tex]
Therefore:
[tex]\begin{gathered} \sin 30\text{ = }\frac{3}{x} \\ \Rightarrow\text{ x = }\frac{3}{\sin 30} \\ x\text{ = }\frac{3}{0.5} \\ x\text{ = 6} \end{gathered}[/tex][tex]\begin{gathered} \cos 30\text{ = }\frac{y}{x}\text{ = }\frac{y}{6} \\ y\text{ = 6cos30} \\ y\text{ = }6\cdot\text{ }\frac{\sqrt[]{3}}{2} \\ y\text{ = 3 }\sqrt[]{3} \end{gathered}[/tex]
Those are the values of x and y.
Note: The values of sin30 and cos30 are their standard values.
