Answer :
A particular brand of gasoline has a density of 0.737 g/mL at 25°C. How many grams of this gasoline would fill a 16.0 gal tank (1 US gal = 3.78 L)?
We are given the density in g/mL of the gasoline and the volume that we have to fill in US gal. We can convert the density to g/L and the volume to L to have all the values in the same unit. and then we can find the mass in grams.
We are given the conversion between US gal and L, let's use it to convert the volume of the tank to L.
1 US gal = 3.78 L
volume of tank = 16.0 US gal * 3.78 L/(1 US gal) = 60.5 L
volume of tank = 60.5 L
Now we can convert the density from g/mL to g/L, since we know that there are 1000 mL in 1 L.
1000 mL = 1 L
density of gasoline = 0.737 g/mL * 1000 mL/(1 L) = 737 g/L
density of gasoline = 737 g/L
Finally we know that we can express the density like the mass divided by the volume. We know the volume and the density, so we can find the mass:
Density = mass / volume
mass = density * volume
mass = 737 g/L * 60.5 L
mass of gasoline = 44600 g
44600 g of the gasoline would fill a 16.0 gal tank.
