A sample of glass that has a mass of 6.0 g gives off 12 J of heat . If the temperature of the sample changes by 4.0 degrees C during this change , what is the specific heat of the glass ? Use the equation c=Q/(m* TRIANGLE T)



Answer :

Answer:

[tex]c=0.5J\text{/g}^0C[/tex]

Explanations:

The formula for calculating the amount of heat is expressed as;

[tex]Q=mc\triangle t[/tex]

where:

• m is the ,mass, of the glass

,

• c is the ,specific heat, of glass

,

• △t is the ,change in temperature

Given the following parameters

m = 6.0g

Q = 12Joules

△t = 4.0 degrees C

Substitute

[tex]\begin{gathered} c=\frac{Q}{m\triangle t} \\ c=\frac{12J}{6g\times4.0^0C} \\ c=\frac{0.5J}{g^0C\text{ }} \end{gathered}[/tex]

Hence the specific heat of the glass is 0.5J/g0C