The circumference is given by:
[tex]\begin{gathered} C=2\pi r \\ so\colon \\ C=28\pi \\ 28\pi=2\pi r \\ r=\frac{28\pi}{2\pi} \\ r=14 \end{gathered}[/tex]
Since we know the radius, we can find the area as follows:
[tex]\begin{gathered} A=\pi r^2 \\ A=\pi(14)^2 \\ A=196\pi \\ A\approx615.75in^2 \end{gathered}[/tex]
Answer:
615.75 in²
