Susy had a square plot of grass in her backyard, but now part of the plot is taken up by a fountain. Each side of the plot has a length of 14.5 feet. One side of the plot has a semicircular fountain with a radius of 2.5 feet.What is the approximate area of the plot of grass after installing the fountain?

Susy had a square plot of grass in her backyard but now part of the plot is taken up by a fountain Each side of the plot has a length of 145 feet One side of th class=


Answer :

Given:-

Susy had a square plot of grass in her backyard, but now part of the plot is taken up by a fountain. Each side of the plot has a length of 14.5 feet. One side of the plot has a semicircular fountain with a radius of 2.5 feet.

To find:-

The approximate area of the plot of grass after installing the fountain.

Now we find the area of square plot,

[tex]14.5\times14.5=210.25[/tex]

Now we find the area of semi circle. we get,

[tex]\begin{gathered} \frac{1}{2}\pi r^2=\frac{1}{2}\times\frac{22}{7}\times2.5\times2.5 \\ \text{ =}\frac{11}{7}\times2.5\times2.5 \\ \text{ =9.821} \end{gathered}[/tex]

So to find the area of plot grass after installing the fountain. we substract both the areas. so we get,

[tex]210.25-9.821=200.429[/tex]

So the area of plot is 200.429 square feet.