Given:
[tex]\begin{gathered} 3+2\times(4^2+1) \\ 5^2+6\times2 \\ 24-(8\div2)^2 \end{gathered}[/tex]Required:
To solve the given equation.
Explanation:
Consider
[tex]\begin{gathered} 3+2\times(4^2+1) \\ =3+2\times(16+1) \\ =3+2\times(17) \\ =3+34 \\ =37 \end{gathered}[/tex][tex]\begin{gathered} 5^2+6\times2 \\ =25+12 \\ =37 \end{gathered}[/tex][tex]\begin{gathered} 24-(8\div2)^2 \\ =24-4^2 \\ =24-16 \\ =8 \end{gathered}[/tex]Final Answer:
[tex]\begin{gathered} 3+2(4^2+1)=37 \\ 5^2+6\times2=37 \\ 24-(\frac{8}{2})^2=8 \end{gathered}[/tex]