Answer:
6
Explanation:
Given the below system of equations;
[tex]\begin{gathered} 4x-3y=6\ldots\ldots\ldots\text{Equation 1} \\ 6x+y=10\ldots\ldots\ldots\text{Equation 2} \end{gathered}[/tex]
If we multiply the first equation by 2, we'll have;
[tex]8x-6y=12\ldots\ldots\text{.Equation 3}[/tex]
To be able to eliminate a variable by adding, we can notice that if multiply Equation 2 by 6. If we do, we'll have;
[tex]36x+6y=60\ldots\ldots\ldots\text{Equation 4}[/tex]
If we add Equation 3 and 4, we'll have;
[tex]\begin{gathered} (36+8)x+(-6+6)y=60+12 \\ 44x+0y=72 \\ 44x=72 \end{gathered}[/tex]
So if we multiply the second equation by 6, we will be able to eliminate a variable as seen above.
