The given equation is:
[tex]y+2=2(x+15)^2[/tex]
Given a quadratic equation in vertex form:
[tex]\begin{gathered} y=a(x-h)^2+k \\ \text{ The vertex is given by the point }(h,k) \end{gathered}[/tex]
Rewrite the given equation in vertex form:
[tex]\begin{gathered} y=2(x+15)^2-2 \\ y=2(x-(-15))^2+(-2) \end{gathered}[/tex]
In this case, h = -15 and k = -2.
Therefore, the required vertex is (-15, -2)
