Answer :
Answer;
The exit temperature = 5333.33 K
Explanation:The inlet pressure: P₁ = 150 kpa
The inlet temperature T₁ = 400K
The exit pressure, P₂ = 2 MPa = 2000 kPa
The exit tenperature, T₂ = ?
The relationship between temperature and pressure for an isentropic process is shown below
[tex]\frac{T_2}{T_1}=\frac{P_2}{P_1}[/tex]Substitute the given parameters into the formula and solve for T₂
[tex]\begin{gathered} \frac{T_2}{400}=\frac{2000}{150} \\ \\ T_2=400(\frac{2000}{150}) \\ \\ T_2=5333.33K \\ \end{gathered}[/tex]The exit temperature = 5333.33 K
