[tex]\begin{gathered} 3x-8\le23\text{ (1)} \\ -4x+26\ge6\text{ (2)} \\ \text{Multiply (2) by -1} \\ 4x-26\le-6\text{ (3)} \\ \text{ Solve for x:} \\ 4x\le-6+26 \\ 4x\le20 \\ x\le5 \\ \text{Evaluate x into (1)} \\ 3(5)-8\le23 \\ 15-8\le23 \\ \text{Which is true} \end{gathered}[/tex]
Therefore:
[tex]x\le5[/tex]
