We have the next equation
[tex]9x^2+6x+1=0[/tex]
we will use the second- degree general formula
[tex]x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]
In our case
a=9
b=6
c=1
we substitute
[tex]x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4(9)(1)}}{2(9)}[/tex]
we simplify
[tex]x_{1,2}=\frac{-6\pm\sqrt[]{36-36}}{2(9)}=-\frac{1}{3}[/tex]
As we can see we have one real solution with a multiplicity of 2
ANSWER
one real solution with multiplicity 2
