Hello I need help with question 9! I will give you a great rating! Please help, I’m not sure how to do this. Also this is not a quiz this is practice

Hello I need help with question 9 I will give you a great rating Please help Im not sure how to do this Also this is not a quiz this is practice class=


Answer :

Given

Angle = 60°

hypotenuse = 32 units.

Solving for x

Adjacent to angle 60°, is side length x, we can therefore use the cosine function to solve for x

[tex]\begin{gathered} \cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}} \\ \cos60\degree=\frac{x}{32} \\ x=32\cdot\cos60\degree \\ x=32\cdot0.5 \\ x=16 \end{gathered}[/tex]

Therefore x = 16.

Solving for y

The opposite to angle 60° is side length y, we can use the sine function to solve for y

[tex]\begin{gathered} \sin\theta=\frac{\text{opposite}}{\text{hypotenuse}} \\ \sin60\degree=\frac{y}{32} \\ y=32\cdot\sin60\degree \\ y=32\cdot\frac{\sqrt{3}}{2} \\ y=16\sqrt{3} \end{gathered}[/tex]

Therefore, y = 16√3.