We have
[tex]2y+8x=2[/tex]In order to obtain easily the table, we need to clear y
[tex]\begin{gathered} 2y=-8x+2 \\ y=\frac{-8x+2}{2} \\ y=-4x+1 \end{gathered}[/tex]then we evaluate for values of x
if x=0
y=-4(0)+1=1
y=1
if x=1
y=-4(1)+1=-3
y=3
if x=2
y=-4(2)+1=-7
y=-7
if x=3
y=-4(3)+1=-11
y=-11
So the table for the given equation is
x y
0 1
1 -3
2 -7
3 -11