Given:
The revenue function is,
[tex]s(x)=0.6x^3-10.2x^2+32.4x+127.2[/tex]
Here, x is the number of months since the beginning of year.
For 3 rd month,
[tex]\begin{gathered} s(3)=0.6(3)^3-10.2(3)^2+32.4(3)+127.2 \\ =16.2-91.8+97.2+127.2 \\ =148.8 \end{gathered}[/tex]
For 6th month,
[tex]\begin{gathered} s(6)=0.6(6)^3-10.2(6)^2+32.4(6)+127.2 \\ =129.6-367.2+194.4+127.2 \\ =84 \end{gathered}[/tex]
So, between 3rd and 6 th months,
[tex]148.8-84=64.8[/tex]
For clothing,
[tex]f(3)-f(6)=140-100=40_{}[/tex]
Between 3rd and 6th month the revenue earned is decreases at faster rate than the revenue earned from sales of clothing.
