Let x represent the number of the days the saw is rented and y represents the charge to the user in dollar
There is a $40 fee (constant) to rent a chain saw plus $9 per day (9x)
a) m is the charge per day
b is the constant
[tex]y=9x+40[/tex]b) Find y when x=5
[tex]\begin{gathered} y=9(5)+40 \\ y=45+40 \\ y=85 \end{gathered}[/tex]For 5 days of rent the saw the charge is $85
Ordered pair (5,85)
c) if the total charge is $184, for how many days is the saw rented?
Solve x when y=184
[tex]\begin{gathered} 184=9x+40 \\ 184-40=9x \\ 144=9x \\ x=\frac{144}{9} \\ \\ \\ x=16 \end{gathered}[/tex]The saw was rented for 16 days