Answer :

It is given that

A stone is thrown into a pond, A circular ripple spreads over the pond in such a way that the radius is increasing at a rate of 2.5 feet per second.

In one second the increment in radius is 2.5 feet

After t seconds, the increment in radius is given by

[tex]r(t)=2.5t[/tex]

The area of the circular ripple is

[tex]A(r)=\pi r^2[/tex]

[tex](A\circ r)(t)=A\lbrack r(t)\rbrack[/tex]

Substitute r(t)=2.5t, we get

[tex](A\circ r)(t)=A\lbrack2.5t\rbrack[/tex]

[tex]UseA(r)=\pi r^2,\text{ we get}[/tex]

[tex](A\circ r)(t)=\pi(2.5t)^2[/tex]

The required function is

[tex](A\circ r)(t)=6.25\pi t^2[/tex]

Hence the fourth option is correct.