Answer :

Given

[tex]\begin{gathered} \angle D=\angle G \\ HE=FE \end{gathered}[/tex][tex]\begin{gathered} In\text{ }\Delta^{\prime}s\text{ EFG and EHD} \\ \angle D=\angle G\text{ (Given)} \\ HE=FE\text{(Given)} \\ \angle HED=\angle FED\text{ (}V.O.A\text{)} \\ \Delta EFG\cong\Delta EHD(AAS) \end{gathered}[/tex]