Given:
[tex]y=2\sin(3x-\frac{\mu}{7})+5[/tex]
Required:
To find the amplitude and period of the given sine function.
Explanation:
Consider
[tex]y=2\sin(3x-\frac{\mu}{7})+5[/tex]
Here the amplitude is 2.
And the period is
[tex]=\frac{2\pi}{3}[/tex]
Final Answer:
Amlitude = 2 and period is
[tex]\frac{2\pi}{3}[/tex]
