If g(n) varies inversely with n and g(n)= 11 when n=2 then find the value of n wheng(n)= 8Round final answer to the tenths place. If answer is a whole number then put a zeroin the tenths place before entering your answer. Work must be shown



Answer :

Given:

g(n) varies inversely with n

so,

[tex]\begin{gathered} g(n)\propto\frac{1}{n} \\ g(n)=\frac{k}{n} \end{gathered}[/tex]

Where (k) is the proportionality constant

We will find the value of (k) using the given condition

When n = 2, g(n) = 11

Substitute with n and g(n)

[tex]11=\frac{k}{2}\rightarrow k=22[/tex]

So, the relation between g(n) and (n) will be:

[tex]g(n)=\frac{22}{n}[/tex]

We will find the value of (n) when g(n) = 8

So, substitute with g(n):

[tex]\begin{gathered} 8=\frac{22}{n} \\ \\ n=\frac{22}{8}=2.75 \end{gathered}[/tex]

Rounding the answer to the nearest tenth

so, the answer will be:

[tex]n=2.8[/tex]