Solving Right triangles where the two legs are given.Equation no. 1: Triangle ABC is right angled at C. if a = 18.5 and b = 14.2. Find ∠A, ∠B and c.Provide your summary.



Answer :

Answer:

• m∠A=52.5°

,

• m∠B=37.5°

,

• c=23.3

Explanation:

Given the right triangle below:

(a)∠A

• The side length ,opposite angle A ,=18.5

,

• The side length ,adjacent to angle A ,=14.2

From trigonometrical ratios:

[tex]\begin{gathered} \tan A=\frac{BC}{AC} \\ \implies\tan A=\frac{18.5}{14.2} \\ A=arctan(\frac{18.5}{14.2}) \\ m\angle A=52.5\degree \end{gathered}[/tex]

The measure of angle A is 52.5°.

(b)∠B

• The side length ,opposite angle A ,=14.2

,

• The side length ,adjacent to angle A ,=18.5

From trigonometrical ratios:

[tex]\begin{gathered} \tan B=\frac{AC}{BC} \\ \implies\tan B=\frac{14.2}{18.5} \\ B=arctan(\frac{14.2}{18.5}) \\ m\angle B=37.5\degree \end{gathered}[/tex]

The measure of angle B is 37.5°.

(c)To find the length of c, apply the Pythagorean theorem.

[tex]\begin{gathered} c=\sqrt{a^2+b^2} \\ c=\sqrt{18.5^2+14.2^2}=\sqrt{543.89} \\ c\approx23.3 \end{gathered}[/tex]

Thus:

• m∠A=52.5°

,

• m∠B=37.5°

,

• c=23.3

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