SOLUTIONS
Let the cost of one CD be c
Let the cost of one books be b
since Sarah can buy one CD and 2 books for $28
and also 2 CD and 3 books for $48
[tex]\begin{gathered} c+2b=28............(1) \\ 2c+3b=48..........(2) \end{gathered}[/tex]
Using substitution method
[tex]\begin{gathered} from\text{ equ\lparen1\rparen} \\ c=28-2b..........(3) \end{gathered}[/tex]
sub the value of c in equ(2)
[tex]\begin{gathered} 2c+3b=48 \\ 2(28-2b)+3b=48 \\ 56-4b+3b=48 \\ -b=48-56 \\ -b=-8 \\ b=8 \end{gathered}[/tex]
sub the value of b in equ(3)
[tex]\begin{gathered} c=28-2b \\ c=28-2(8) \\ c=28-16 \\ c=12 \end{gathered}[/tex]
Therefore the cost of a CD = 12 and the cost of a book = 8
