Given:
The side of a parallelogram is, b1 = 6 mm.
The height of a parallelogram is, h1 = 4 mm.
The base of a triangle is, b2 = 8 mm.
The height of a triangle is, h2 = 2 mm.
The objective is to find the area of the figure.
The area of the figure can be calculated as,
[tex]\begin{gathered} A=\text{Area of parallelogram+Area of triangle.} \\ A=(b_1\cdot h_1)+(\frac{1}{2}\cdot b_2\cdot h_2) \end{gathered}[/tex]
Now, substitute the given values in the above formula.
[tex]\begin{gathered} A=(6\cdot\cdot4)+(\frac{1}{2}\cdot8\cdot2) \\ A=24+8 \\ A=32mm^2 \end{gathered}[/tex]
Hence, the area of the figure is 32 square millimeter.
