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A parking garage in the city charges $2.75 for the first hour and $1.25 for each additional hour, x. Write and solve an inequality to find the maximum time of additional hours that Tony can park his car at the garage if he wants to pay less than $8



Answer :

$2.75 first hour

$1.25 additional hour

Tony wants to pay less than $8.

Then:

$8= $2.75 + $1.25x

[tex]\begin{gathered} 8\leq\text{ 2.75 + 1.25x} \\ 8\text{ - 2.75= 1.25x} \\ 5.25=\text{ 1.25x} \\ \\ \frac{5.25}{1.25}=\text{ x} \\ \\ 4.2\text{ additional hours. } \end{gathered}[/tex]

Then the maximum time of additional hours that Tony can park his car at the garage if he wants to ay less than $8 is 4 hours.

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