Answer: We are going to solve the following systems of equations.
[tex]\begin{gathered} y=x^2+2x-2\rightarrow(1) \\ y=5x-4.25\rightarrow(2) \end{gathered}[/tex]substituting equation (2) in (1) gives:
[tex]\begin{gathered} 5x-4.25=x^2+2x-2 \\ \therefore\rightarrow \\ -x^2+3x-2.25=0 \\ x=\frac{3}{2} \end{gathered}[/tex][tex]\begin{gathered} \therefore\rightarrow \\ y=5(\frac{3}{2})-4.25=7.5-4.25=3.25 \end{gathered}[/tex][tex]\begin{gathered} \therefore\rightarrow \\ x=\frac{3}{2} \\ y=3.25 \end{gathered}[/tex]