we have that
[tex]\begin{gathered} \frac{2x+3+14}{x-5+6}=\frac{14}{x-5} \\ \frac{2x+17}{x-1}=\frac{14}{x-5} \\ (x-5)(2x+17)=14(x-1) \\ 2x^2+7x-85=14x-14 \\ 2x^2-7x-71=0 \\ x=\frac{7+\sqrt[]{49+568}}{4}=\frac{7+\sqrt[]{617}}{4}\approx7.96 \end{gathered}[/tex]
