Use pythagorean theorem to find missing sides as follow:
[tex]hypotenuse^2=Leg1^2+Leg2^2[/tex]
In triangle 1 frin the hypotunuse (MT) knowing that the legs are 3m and 13m:
[tex]\begin{gathered} MT^2=(13m)^2+(3m)^2 \\ MT^2=169m^2+9m^2 \\ MT^2=178m^2 \\ MT=\sqrt{178}m \end{gathered}[/tex]
In triangle 2 find the hypotenuse (TL) knwing that the legs are 2m and 3m:
[tex]\begin{gathered} TL^2=(3m)^2+(2m)^2 \\ TL^2=9m^2+4m^2 \\ TL^2=13m^2 \\ TL=\sqrt{13}m \end{gathered}[/tex]
Add the lengths to get the perimeter:
[tex]\begin{gathered} P=MT+TL+ML \\ P=\sqrt{178}m+\sqrt{13}m+15m \\ P\approx31.95m \end{gathered}[/tex]Then, the perimeter of the triangle MLT is (√178 +√13+15)m or approximately 31.95 m
