Answer:
The values of x and y are;
[tex]\begin{gathered} x=4 \\ y=9 \end{gathered}[/tex]
Explanation:
Given the figure in the attached image.
[tex]\begin{gathered} (16y)^0=(18y-18)^0\text{ --------(vertically opposite angles)} \\ (10x-4)^0=6(x+2)^0\text{ --------(vertically opposite angles)} \end{gathered}[/tex]
Solving the first equation we have;
[tex]\begin{gathered} 16y=18y-18 \\ 16y-18y=-18 \\ -2y=-18 \\ \text{divide both sides by -2;} \\ \frac{-2y}{-2}=\frac{-18}{-2} \\ y=9 \end{gathered}[/tex]
solving the second equation;
[tex]\begin{gathered} 10x-4=6(x+2) \\ 10x-4=6x+12 \\ 10x-6x=12+4 \\ 4x=16 \\ x=\frac{16}{4} \\ x=4 \end{gathered}[/tex]
Therefore, the values of x and y are;
[tex]\begin{gathered} x=4 \\ y=9 \end{gathered}[/tex]
